WebPlease scroll down to see the correct answer and solution guide. Right Answer is: A SOLUTION Since a, b, c, d are in H.P., therefore b is the H.M. of a and c i.e., b = 2ac b+d, ∴ (a+c)(b+d) = 2ac b. 2bd c ⇒ ab+ad+bc+cd = 4ad ⇒ ab+bc+cd = 3ad Trick : Check for a =1, b = 1 2, c = 1 3, d = 1 4 Web4 4 , 8 8 , 16 16 , 32 32 , 64 64 , 128 128. This is a geometric sequence since there is a common ratio between each term. In this case, multiplying the previous term in the sequence by 2 2 gives the next term. In other words, an = a1rn−1 a n = a 1 r n - 1. Geometric Sequence: r = 2 r = 2.
The 4th term of an HP is 3/5 and the 8th term is 1/3. Then its 6th ...
WebThe 7th term ... Question The 7th term of an AP is -4 and its 13th term is - 16. Find the AP. Solution The nth term of an AP is given by a+ (n-1)d. As per the question, a+6d= −4 a+12d= −16 Subtracting we get, 6d =−12 ⇒ d= −2 Now, a+6×(−2) =−4 ⇒ a= 8 So, the AP is 8, 6, 4, 2, 0, -2, -4 ..... Suggest Corrections 28 Similar questions Q. WebKnow more of this type cracks? The expeliarmus spell, the hoyo who lived are ones that come to my head, but i mean fics that are literaly crack on OP on CRACK. Not like seventh horcrux, its well written comedy. Maybe make a wish count. oster cyclomatic blender manufacture date
[Solved] If the 7th term of an arithmetic progression is 1/9 and its
WebAnswer: Option B. Explanation: Now from the above HP formulae, it is clear the reciprocals of first 11 terms will make an AP. The sum of first 11 terms of an AP = [2a + (11 – 1) d] … Web16 aug. 2024 · If 8th and 14th term of an HP are 1/2 and 1/3 respectively find 20th term See answers Advertisement Advertisement siddhartharao77 siddhartharao77 Given 8th term of an HP = (1/2) = > 1/(a + 7d) = (1/2) = > a + 7d = 2 ----- (1)----- Given 14th term of an HP is 1/3. = > 1/(a + 13d) = (1/3) = > a + 13d = 3 ----- (2) ... Web9 jun. 2024 · If the 7th term of a HP is 8, and the 8th term is 7 then its 15th term is Advertisement sathvikshetty23 is waiting for your help. Add your answer and earn points. … oster day light